The total energy of an electron in the first excited state of hydrogen atom is -3.4eV. What is the kinetic energy of the electron in this state ?

The total energy of an electron in the first excited state of hydrogen

1.	The total energy of an electron in the first excited state of hydrogen atom is -3.4eV. What is the kinetic energy of the electron in this state ?
Answer» 2.55 eV 4.25 eV 11.25 eV 19.55 eV Solution :(d) ENERGY of photon corresponding to second line to Balmer SERIES for `Li^(2+)` ion `=(13.6)xx(3)^2 [1/(2^2) - 1/(4^2)] = 13.6 xx (27)/(16) = 22.95 eV` Energy needed to REJECT electron from N = 2 level in H - atom`=13.6 xx 1^2 [1/(2^2) - 1/(oo^2)]` `=(13.6)/(4) eV = 3.4 eV` `Delta E = 22.95 - 34 = 19 .55 eV`