The total energy of an electron in the first excited state of the hydr – InterviewSolution

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1.	The total energy of an electron in the first excited state of the hydrogen atom is -3.4eV. What is the potential energy of the electron in this state ?
Answer» In `1^(st)` orbit, E=-3.4 eV Total energy `E=(KZe^(2))/(2r)-(KZe^(2))/(r )` `(KZ e^(2))/(r )=U` (say) `E=(u)/(2)-u=(-u)/(2)` `U=-2E` `therefore U=-2xx-3.4=6.8 eV`.

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