The total energy of an electron in the first excited state of the hydr – InterviewSolution

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1.	The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV. What is the potential energy of the electron in this state ?
Answer» We know kinetic energy of electron `=(Kze^(2))/(2r)` and P.E of electron `=(-Kze^(2))/(r)` P.E.=-2 (kinetic energy) In this calculation electric potential and hence potential energy is zero at infinity. Total energy = PE + KE = -2KE + KE = -KE P. E of electron in this first excited state `= -2KE = -2 xx 3.4-= 6.8 eV. `

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