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The total energy of the body excuting `S.H.M.` is `E` . Then the kinetic energy when the displacement is half of the amplitude, isA. `(E )/(2)`B. `(E )/(4)`C. `(3E)/(4)`D. `(sqrt(3))/(4)E` |
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Answer» Correct Answer - C The total ………….. kinetic energy `=(1)/(2)m omega^(2)(a^(2)-x^(2))` kinetic energy `= (1)/(2) ((3)/(4)m omega^(2)a^(2)) = (3E)/(4)` |
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