1.

The total energy of the body excuting `S.H.M.` is `E` . Then the kinetic energy when the displacement is half of the amplitude, isA. `(E )/(2)`B. `(E )/(4)`C. `(3E)/(4)`D. `(sqrt(3))/(4)E`

Answer» Correct Answer - C
The total …………..
kinetic energy `=(1)/(2)m omega^(2)(a^(2)-x^(2))`
kinetic energy `= (1)/(2) ((3)/(4)m omega^(2)a^(2)) = (3E)/(4)`


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