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The total energy of the electron of H-atom in the second quantum state is -E_(2). The total energy of the He^(+) atom in the third quantum state is: |
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Answer» `-((3)/(2))E_(2)` `=-(Z^(2))/(n^(2))xx13.6eV` `E_(2)(H)=-(13.6)/(1)eV` `E_(3)(He^(+))=-(13.6xx4)/(9)eV` `(E_(2))/(E_(3))=(9)/(4)"or"E_(3)=(4)/(9)E_(2)`. For negative value of `E_(2),E_(3)` will also be negative. |
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