1.

The total energy of the electron of H-atom in the second quantum state is -E_(2). The total energy of the He^(+) atom in the third quantum state is:

Answer»

`-((3)/(2))E_(2)`
`-((2)/(3))E_(2)`
`-((4)/(9))E_(2)`
`-((16)/(9))E_(2)`

Solution :Energy of electrons in N TH state
`=-(Z^(2))/(n^(2))xx13.6eV`
`E_(2)(H)=-(13.6)/(1)eV`
`E_(3)(He^(+))=-(13.6xx4)/(9)eV`
`(E_(2))/(E_(3))=(9)/(4)"or"E_(3)=(4)/(9)E_(2)`.
For negative value of `E_(2),E_(3)` will also be negative.


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