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The total number of correct order of ionisation energy is : `(Ne gt Ne^(+)),(O^(-) lt O),(N^(+) gtN), (Fe lt Fe^(2+)),(O^(-) gt O^(-2)), (F gt F^(-)),(Na gt Na^(+)), (Mg lt Mg^(2+)), (Na^(+) lt Mg^(2+)),(S^(-2) lt Cl^(-))` |
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Answer» Correct Answer - 4 `10=(n(n-1))/(2)` `n=5` `4^(th)` excited state |
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