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The total number of electrons present in `18 mL` of water is …… |
Answer» Correct Answer - A::B::C::D The total numbe of electrons present in `18 mL` of water is `6.023 xx 10^(24)`. Number of electron in one molecules of `H_(2) O` is `2 + 8 = 10` Denisty = 1 `18 mL` means `18 g` Moles `= (18)/(18) = 1` Moles `= 6.023 xx 10^(23)` Electrons `= 6.023 xx 10^(23) xx 10 = 6.023 xx 10^(24)` |
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