1.

The total number of electrons present in 4.6 g ofsodium is

Answer»

1 mole Na contains 23 g Na

23 g Na =1 mole of Na

1 g Na= 1/23 moles of Na

4.6 g Na= 1/23×4.6= 4.6/23=0.2 moles

Now, 0.2 moles => 0.2 × (6.022 x 10^23) atoms = 1.2 × 10^23 atoms

1 neutal Na atom has 11 electrons=> 1.2 × 10^23 atoms contains= 1.2 × 10^23 × 11 electrons= 13.2 × 10^23 electrons


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