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The total number of electrons present in all `s` orbitals, all the `p` orbitals, and all the `d` orbitals of cesium ion are, respectively,A. `8, 26, 10`B. `10, 24, 20`C. `8, 22, 24`D. `12, 20, 22` |
Answer» Correct Answer - B The atomic numbe rof cseium is `55`. Therefore, its ground state electron configuration is `1s^(2)2s^(2)2p^(6)3s^(6)3d^(10)4s^(2)4d^(6)4d^(10)5s^(2)5p^(6)6s^(1)` or simply, `[Xe] 6s^(1)` `Cs^(+)` ion will have `Xe` configuration. Eletron present in the `s` subshell `= 5xx2 = 10` Electrons present in the `p` subshell `= 4 xx 6 = 24` Electron present in the `d` subshell `= 10 xx2 = 20` |
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