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The total number of possibel coordination isomer for the given compounds `[Pt(NH_(3))(4)Br_(2)][PtBr_(4)]` is .A. `2`B. `4`C. `5`D. `3` |
Answer» Correct Answer - B `[Pt^(4+)CI_(2)(NH_(3))_(4)]^(2+)[Pt^(2+)CI_(4)]^(2-)` (2) `[Pt^(4+)CI_(3)(NH_(3)]^(o+)[Pt^^(2+)CI_(3)(NH_(3))]^(o+)` (3) `[Pt^(2+)CI(NH_(3))_(3)]^(o+)[Pt^(4+)CI_(5)(NH_(3))]^(Θ)` (4) `[Pt^(2+)(NH_(3))_(4)]^(2+)[Pt^(4+)CI_(6)]^(2-)` . |
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