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The total number of protons in 10g of calcium carbonate is `(N_(0) = 6.023xx10^(23))`A. `1.5057xx10^(24)`B. `2.0478xx10^(24)`C. `3.0115xx10^(24)`D. `4.0956xx10^(24)` |
Answer» Correct Answer - C Protons in 1 mole `CaCO_(3)` = atomic number Ca + atomic number C+3`xx`atomic number O `20+6+24 = 50` moles Protons in 10 g `= (10)/(100)xx50xx6.02xx10^(23)` `=3.01xx10^(24)` |
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