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The total number of ways in which 5 balls of differert colours can be distributed among 3 persons so thai each person gets at least one ball isA. 75B. 150C. 210D. 243 |
Answer» Correct Answer - B `{:("Objects", "Groups", "Objects", "Groups"),("Distinct", "Distinct", "Identical", "Identical"),("Distinct", "Identical", "Identical", "Distinct"):}` Description of Situation Here, 5 distinct balls are distributed amongst 3 persons so that each gets at least one ball. i.e. `"Distinct " to " Distinct"` So, we should make cases `"Case I " {:(A, B, C),(1, 1, 2):}} " ""Case II " {:(A, B, C),(1, 2, 2):}}` Number of ways to distribute 5 balls `= (""^(5)C_(1) * ""^(4)C_(1) * ""^(3)C_(3) xx (3!)/(2!)) + (""^(5)C_(1) * ""^(4)C_(2) * ""^(2)C_(2) xx (3!)/(2!))` `= 60 + 90 = 150` |
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