The total numebr of electrons present in 18 mL of water density=1gmL^(

1.	The total numebr of electrons present in 18 mL of water density=1gmL^(-1) is
Answer» `6.02 xx 10^(23)` `6.02 xx 10^(23)` `6.02 xx 10^(24)` `6.02 xx 10^(25)` Solution :C) 18 mL `H_(2)O` = 18g of `H_(2)O` = 1MOL `=6.02 xx 10^(23)` molecules `= 10 xx 6.02 xx 10^(23)` electrons `6.02 xx 10^(24)` electrons

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