1.

The total pressure for volatile components A and B is 0.02 bar at equilibrium. If the mole fractions at component A is 0.2, then, what will be the partial pressure of component B ?

Answer»

0.02 BAR
0.04 bar
0.016 bar
0.2 bar

Solution :`X_(A)+X_(B)=1`
`THEREFORE 0.2+X_(B)=1 "" therefore X_(B)=0.8`
`p_(B)=p.X_(B)=(0.02)(0.8)`
`therefore p_(B)=0.016` bar


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