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The train travels the first 30 km of 120 km track with a uniform speed of 30 km per hour what will the speed of the train to cover the remaining distance of a track so that its average speed is 60 km |
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Answer» Answer: 90kmph Explanation: speed of first 30km, s1 = 30kmph remaining DISTANCE to cover = 120-30=90km speed of LAST 90km,s2 = x kmph average speed = (s1+s2)/2 60 kmph = (30+x)/2 120 = (30+x) x = 120-30 x=90 kmph
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