The trajectory of a particle in a vertical plane is 4y=3x−x24, x and y are the horizontal and vertical distances of the projectile from the point of projection. The angle of projection from the horizontal and the maximum height attained by the particle are

The trajectory of a particle in a vertical plane is 4y=3x−x24, x and

1.	The trajectory of a particle in a vertical plane is 4y=3x−x24, x and y are the horizontal and vertical distances of the projectile from the point of projection. The angle of projection from the horizontal and the maximum height attained by the particle are
Answer» The trajectory of a particle in a vertical plane is $4 y = 3 x - \frac{x^{2}}{4}$ , $x$ and $y$ are the horizontal and vertical distances of the projectile from the point of projection. The angle of projection from the horizontal and the maximum height attained by the particle are

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The trajectory of a particle in a vertical plane is 4y=3x−x24, x and y are the horizontal and vertical distances of the projectile from the point of projection. The angle of projection from the horizontal and the maximum height attained by the particle are

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