1.

The trajectory of a projectile in a vertical plane is: y=ax−bx2, where a and b are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is

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The trajectory of a projectile in a vertical plane is: y=axbx2,
where a and b are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is



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