1.

The transition metal ion that has 'spin-only' magnetic moment value of 5.96 is

Answer»

`Mn^(2+)`
`Fe^(2+)`
`V^(2+)`
`Cu^(2+)`

Solution :`Mn^(2+)` ION has the electronic configuration `3d^(5) 4s^(0)`.
No. of unpaired ELECTRONS = 5
`mu_(s) = sqrt(n(n+2))`
` = sqrt(5(5 +2)) = sqrt(35)` = 5.92 BM


Discussion

No Comment Found