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| 1. |
The treatment of alkyl chlorides with aqueous KOH solution leads to the formation of alcohols but in the presence of alcoholic KOH solution, alkenes are the major product. Explain. |
| Answer» Solution :In aqueous solution, KOH is almost completely ionised to give `OH^(-)` IONS which being a strong nucleophile brings about a substitution reaction of alkyl halides to form alcohols. In aqueous solution, `OH^(-)` ions are highly hydrated. This solvation reduces the basic character of `OH^(-)` ions which therefore, abstract fails to abstract a HYDROGEN atom from the `beta`-carbon of the alkyl chloride to form an alkene. In CONTRAST, an ALCOHOLIC solution of KOH contains alkoxide (`RO^(-)`) ions which being a much stronger base than `OH^(-)` ions preferentially eliminates a molecule of HCI from an alkyl chloride to form ALKENES. | |