1.

The treatment of alkyl chlorides with aqueous KOH solution leads to the formation of alcohols but in the presence of alcoholic KOH solution, alkenes are the major product. Explain.

Answer»

Solution :In aqueous solution, KOH is almost completely ionised to give `OH^(-)` IONS which being a strong nucleophile brings about a substitution reaction of alkyl halides to form alcohols. In aqueous solution, `OH^(-)` ions are highly hydrated. This solvation reduces the basic character of `OH^(-)` ions which therefore, abstract fails to abstract a HYDROGEN atom from the `beta`-carbon of the alkyl chloride to form an alkene. In CONTRAST, an ALCOHOLIC solution of KOH contains alkoxide (`RO^(-)`) ions which being a much stronger base than `OH^(-)` ions preferentially eliminates a molecule of HCI from an alkyl chloride to form ALKENES.


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