1.

The treatment of CH_3MgXwith CH_3 C -= C -H produces

Answer»

`CH_4`
`CH_3-CH = CH_2`
`CH_3C -= C-CH_3`
`CH_3-OVERSET(H)overset(|)C= overset(H)overset(|)C-CH_3`

SOLUTION :`CH_3C -= CH = CH_3 MgX to CH_3 C -=CMgX + CH_4`


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