Saved Bookmarks
| 1. |
The triangle of maximum area inscribed in a circle is : |
|
Answer» equilateral `THEREFORE Delta ABC` is isosceles triangle. Area of `Delta ABC` is `Z=(1)/(2)xx AB xx CD` `= a^(2)sin 2theta(1+cos 2theta)` `therefore (dz)/(d THETA)=2a^(2)(cos 4theta + cos 2theta)=0` `rArr 2 cos 3theta cos theta = 0` `rArr theta = (pi)/(2)` or `theta = (pi)/(6)` `therefore theta = (pi)/(2)` is impossible, `therefore` at `theta = (pi)/(6)` area of triangle is maximum. |
|