1.

The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celcius and Fahrenheit scales.

Answer»

Tc = T – 273.15

∴ Tc for neon = 24.57 – 273.15

= – 248.58°C

and Tc for carbon dioxide

= 216.55 – 273.15

= – 56.60°C

tF\(\frac{9}{5}\)tc + 32

∴ tF for neon = \(\frac{9}{5}\) × (-248.58) + 32

= – 415.44°C

tF for carbon dioxide

\(\frac{9}{5}\) × (-56.60) + 32

= – 69.88°F.



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