The tuning circuit of a radio receiver has a resistance of 50 Ω, an inductor of 10 mH and a variable capacitor. A 1 MHz radio wave produces a potential difference of 0.1 mV. The value of the capacitor to produce the resonance is (take π2=10)

The tuning circuit of a radio receiver has a resistance of 50 Ω, an i

1.	The tuning circuit of a radio receiver has a resistance of 50 Ω, an inductor of 10 mH and a variable capacitor. A 1 MHz radio wave produces a potential difference of 0.1 mV. The value of the capacitor to produce the resonance is (take π2=10)
Answer» The tuning circuit of a radio receiver has a resistance of $50 Ω$ , an inductor of $10 mH$ and a variable capacitor. A $1 MHz$ radio wave produces a potential difference of $0.1 mV .$ The value of the capacitor to produce the resonance is $($ take $π^{2} = 10)$

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The tuning circuit of a radio receiver has a resistance of 50 Ω, an inductor of 10 mH and a variable capacitor. A 1 MHz radio wave produces a potential difference of 0.1 mV. The value of the capacitor to produce the resonance is (take π2=10)

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