The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6

1.	The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6 y + 15 = 0 touch each other. The equation of their common tangent is :
Answer» Common tangent (x²+ y² - 2x + 6y +6) - (x² + y² - 5x + 6y + 15) = 0 = - 2x + 5x + 6y - 6y + 6 - 15 = 0 = 3x - 9 = 0 = x = \(\cfrac93\) = 3 = x = 3 Hence, x = 3 is common tangent

The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6 y + 15 = 0 touch each other. The equation of their common tangent is :

Answer»

Common tangent (x²+ y² - 2x + 6y +6) - (x² + y² - 5x + 6y + 15) = 0

= - 2x + 5x + 6y - 6y + 6 - 15 = 0

= 3x - 9 = 0

= x = \(\cfrac93\) = 3

= x = 3

Hence, x = 3 is common tangent

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The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6 y + 15 = 0 touch each other. The equation of their common tangent is :

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