1.

The two ends of a metal rod are maintained at temperatures 100^(@)C and 110^(@)C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are now maintained at temperatures 200^(@)C and 210^(@)C, the rate of flow of heat will be

Answer»

16.8 j/s
8.0 J/s
4.0 J/s
44.8 J/s

Solution :As we know `(d THETA)/(DT) prop (T_(2)-T_(1)) or (d theta)/(dt) = K (T_(2)-T_(1))`
Case `(i) (d theta_(1))/(dt )= k(110-100) = kxx10 --- (i)`
Case (ii) `(d theta_(2))/(dt)= k(210-200) = kxx10 --- (ii) `
From (i) & (ii) `(d theta_(1))/(dt) = (d theta_(2))/(dt) = 4.0 ` j/s


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