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The two ends of a train moving with uniform acceleration pass a certain point with velocity u and v. Find the velocity with which the middle point of the train passes the same point. |
Answer» SOLUTION : Between `A, B:(V^(1))^(2)-u^(2)=2as//2` Between `B,C:v^(2)-(v^(1))^(2)=2as//2` `implies (v^(1))^(2)-u^(2)=v^(2)-v^(12)` `2(v^(1))^(2)=v^(2)+v^(2)` Velocity at mid POINT is `v^(1)=sqrt((u^(2)+v^(2))/(2))` |
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