The two ions A^(+) and B^(-) have radii 88 and 200 pm respectively. In the close packed crystal of compound AB, predict the corrdination number of A^(+) .

The two ions A^(+) and B^(-) have radii 88 and 200 pm respectively. In

1.	The two ions A^(+) and B^(-) have radii 88 and 200 pm respectively. In the close packed crystal of compound AB, predict the corrdination number of A^(+) .
Answer» Solution :`(r_(+))/(r_(-)) = (R(A^(+)))/(r(B^(-)))= (88"PM")/(200"pm") = 0.44` It lies in the range0.414 to 0.732 HENCE, the cordination number of ` A^(+) = 6`