1.

The two ions A^+ and B^- have radii 88 and 200 pm respectively. In the close packed crystal of compound AB, predict the coordination number of A^+

Answer»

Solution :`r_+/r_(-) =(R(A^+))/(r(B^-))="88pm"/"200pm"=0.44`
it lies in the range 0.414 to 0.732
HENCE, the coordination NUMBER of `A^+`=6


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