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The two ions A^+ and B^- have radii 88 and 200 pm respectively. In the close packed crystal of compound AB, predict the coordination number of A^+ |
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Answer» Solution :`r_+/r_(-) =(R(A^+))/(r(B^-))="88pm"/"200pm"=0.44` it lies in the range 0.414 to 0.732 HENCE, the coordination NUMBER of `A^+`=6 |
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