The two natural isotopes of chlorine viz. \(_{17}^{35}Cl\) and \(_{1

1.	The two natural isotopes of chlorine viz. \(_{17}^{35}Cl\) and \(_{17}^{35}Cl\) exist in relative abundance of 3 : 1. Find out the average atomic mass of chlorine.
Answer» Given : Isotopes of chlorine \(_{17}^{35}Cl\) and \(_{17}^{35}Cl\). Ratio of relative abundance of these isotopes is 3 : 1. To find : Average atomic mass of chlorine Calculation : From the relative abundance 3 : 1, it is understood that out of 4 chlorine atoms, 3 atoms have mass 35 and 1 atom has mass 37. Therefore, The average atomic mass of chlorine = \(\frac{3\times 35+1\times 37}{4}\)= 35.5 ∴ Average atomic mass of chlorine = 35.5 u The average atomic mass of chlorine is 35.5 u.

The two natural isotopes of chlorine viz. \(_{17}^{35}Cl\) and \(_{17}^{35}Cl\) exist in relative abundance of 3 : 1. Find out the average atomic mass of chlorine.

Answer»

Given :

Isotopes of chlorine \(_{17}^{35}Cl\) and \(_{17}^{35}Cl\).

Ratio of relative abundance of these isotopes is 3 : 1.

To find :

Average atomic mass of chlorine

Calculation :

From the relative abundance 3 : 1, it is understood that out of 4 chlorine atoms, 3 atoms have mass 35 and 1 atom has mass 37.

Therefore,

The average atomic mass of chlorine = \(\frac{3\times 35+1\times 37}{4}\)= 35.5

∴ Average atomic mass of chlorine = 35.5 u

The average atomic mass of chlorine is 35.5 u.