The two opposite faces of a cubical piece of iron (thermal conductivity =0.2 CGS units) are at 100∘C and 0∘C. The face at 0∘C is in contact with the ice at 0∘C. If the area of a surface is 4 cm2 and latent heat of fusion of ice is 80 J/g, then the mass of ice melted in 10 minutes will be:

The two opposite faces of a cubical piece of iron (thermal conductivit

1.	The two opposite faces of a cubical piece of iron (thermal conductivity =0.2 CGS units) are at 100∘C and 0∘C. The face at 0∘C is in contact with the ice at 0∘C. If the area of a surface is 4 cm2 and latent heat of fusion of ice is 80 J/g, then the mass of ice melted in 10 minutes will be:
Answer» The two opposite faces of a cubical piece of iron (thermal conductivity $= 0.2 CGS units$ ) are at $100^{\circ} C$ and $0^{\circ} C$ . The face at $0^{\circ} C$ is in contact with the ice at $0^{\circ} C$ . If the area of a surface is $4 {cm}^{2}$ and latent heat of fusion of ice is $80 J/g$ , then the mass of ice melted in $10$ minutes will be:

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The two opposite faces of a cubical piece of iron (thermal conductivity =0.2 CGS units) are at 100∘C and 0∘C. The face at 0∘C is in contact with the ice at 0∘C. If the area of a surface is 4 cm2 and latent heat of fusion of ice is 80 J/g, then the mass of ice melted in 10 minutes will be:

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