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The two planets with radii `R_(1), R_(2)` have densities `rho_(1), rho_(2)`, and atmospheric pressures `p_(1)` and `p_(2)`, respectively. Therefore, the ratio of masses of their atmospheres, neglecting variation of `g` and `rho` within the limits of atmosphere, isA. `(p_(1)R_(2)rho_(1))/(p_(2)R_(1)rho_(2))`B. `(p_(1)R_(2)rho_(2))/(p_(2)R_(1)rho_(1))`C. `(p_(1)R_(1)rho_(1))/(p_(2)R_(2)rho_(2))`D. `(p_(1)R_(1)rho_(2))/(p_(2)R_(2)rho_(1))` |
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Answer» Correct Answer - D `p=rho_(atm)gh=m/(4/3pi[(R+h)^(3)-R] (GM)/(R^(2))h` `implies p=m/(4/3piR^(3)[(1+h/R)^(3)-1)]xx(G4/3piR^(3)l_(0))/(R^(2))xxh` `m/(4/3piR^(3)[(1+(3h)/h-1]xxG4/3piRl_(0)h` (Here `M=4/3piR^(3)l_(0)`) Here `p=(mGrho)/(3R)` `=:. Mprop(pR)/rho` |
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