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The two sides of a triangle having perimeter 10 m are \(2\frac{1}{2}\) m and \(3\frac{1}{2}\) m.What is the ratio of the length of the three sides of triangles? |
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Answer» Perimeter of triangle = 10 m First side = \(3\frac{1}{2}\) m = \(\frac{5}{2}\) m Second side = \(3\frac{1}{2}\) m = \(\frac{7}{2}\) m Third side = 4 m Ratio of three sides of a triangle \(=\frac{5}{2}:\frac{7}{2}:4=5:7:8\) |
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