InterviewSolution
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The two slits in an interference experiment are illuminated by light of wavelength 5600 A. Deter-mine the path difference and phase difference between the waves arriving at the centre of the eighth dark fringe on the screen. |
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Answer» Data : λ = 5600 A = 5.6 × 10-7 m Order of the dark fringe is 8, ∴ m = 8 For the fringe to be dark, path difference = (2m – 1) \(\cfrac λ2\) ∴ Path difference, ∆l = (2 × 8 – 1) \(\cfrac λ2\) = 7.5λ = 7.5 × 5.6 × 10-7 m = 4.2 × 10-6 m Phase difference, φ = \(\cfrac{2\pi}λ\) x ∆l = \(\cfrac{2\pi}{5.6\times10^{-7}}\) × 4.2 × 10-6 = 15π |
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