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The type of isomerism exihibited by the compound with formula `C_(4)H_(10)O` is :A. Chain and positionB. Functional and positionC. MetamerismD. Chain, position, functional, and metamerism

Answer» Correct Answer - D
D.U. in `C_(4)H_(10)O=((2n_(C)+2)-n_(H))/(2)=(10-10)/(2)=0`
It should be alcohol or ether.
(i) Alcohols and ethers are functional isomers.
ii. Alcohol shows position and chain isomerism.
iii. Ether shows position isomerism and metamerism.
So, the compound `(C_(4)H_(10)O)` shows chain, position, functional isomerisms, and metamerism.


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