1.

The uncertainty in momentum of an electron is 1 xx 10^(-5) kg mis. The uncertainty in its position will be (h = 6.62 xx 10^(- 34) kg m^(2)/s)

Answer»

`5.27xx10^(-30)` m
`1.05xx10^(-26)` m
`1.05xx10^(-28)` m
`5.25xx10^(-28)` m

Solution :`DeltaxxxDeltap=h/(4PI)`
(Heisenberg.s UNCERTAINTY PRINCIPLE)
`rArrDeltax=(6.62xx10^(-34))/(4xx3.14xx10^(-5))=5.27xx10^(-30)m`


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