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The uncertainty in the position of a flying dust particle of mass 0.1 mg is found to be 10^(-4)m. The uncertainty in the position of another flying dust particle of mass 0.5 mg is also found to be same If a third flying dust particle of mass 1 mg had the same uncertainty in position as in its velocity, the uncertainty in its momentum would be |
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Answer» `5.2 xx 10^(-28) kg ms^(-1)` Hence, `Delta x (m Delta v) = (h)/(4pi)` gives `x xx (10^(-6) kg xx x) = (6.6 xx 10^(-34) g m^(2) s^(2))/(4 xx 3.14)` or `x^(2) = 52.5 xx 10^(-30) or x = 7.25 xx 10^(-15)` `:. Delta p = m Delta v = 10^(-6) kg xx 7.25 xx 10^(-15) ms^(-1)` `= 7.25 xx 10^(-21) kg m s^(-1)` |
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