1.

The unit cell of an element of atomic mass 108 u and density 10.5 g cm^(-3) is cube with edge length 409 pm. Find the type of unit cell of the crystal. (Given : Avogadro's constant = 6.023 xx 10^(23) mol)

Answer»

Solution :`d = (ZM)/(a^(3)N_(A))`
`Z = (d xx a^(3) xx N_(A))/(M)`
M = 108 u
d = 10.5 `cm^(3)`
a = 409 pm
`Z = (10.5 xx (409 xx 10^(-10))^(3) xx 6.023 xx 10^(23))/(108)`
`= 40056796 xx 10^(-7)`
= 4.0056796
In a FCC UNIT cell, there are four ATOMS per unit cell. So it is fcc.


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