The unit cell of metallic silver Volume of Ag atom is 144.4pm (1) The percent of the empty space

The unit cell of metallic silver Volume of Ag atom is 144.4pm (1) The

1.	The unit cell of metallic silver Volume of Ag atom is 144.4pm (1) The percent of the empty space
Answer» GIVEN, ATOMIC mass of SILVER =108u Atomic cell length, a=4.077×10 −8 cm Atomic radius in FCC, r= 4 a 2 = 4 4.077×10 −8 2 =1.44×10 −8 cm\ Each silver unit cell contains 4 atom. Density = N A ×a 3 4×atomicmassofsilver = 6.02×10 23 ×(4.077×10 −10 ) 3 4×108 =10589.25kgm −3 Hence, atomic radius 1.44×10 −8 cm and density is 10589.25kgm −3