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The unit cube length forLiCl ( NaCl structure) is5.14 Å . Assuming anion -anion contant, calculate the ionicradius for chloride ion. |
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Answer» ` BC = sqrt( AB^(2) + AC^(2))= sqrt((2.57)^(2) + (2.57)^(2)) = 3.63` RADIUS of ` CL^(-)` ion ` 1/2 XX 3.63 Å = 1.81 Å` 
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