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The unit `J Pa^(-1)` is equivalent toA. (a)`m^(3) `B. (b)` cm^(3)`C. (c )` dm^(3)`D. (d)None of these |
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Answer» Correct Answer - A `Jpa^(-1)`, Unit of work is Joule and unit of pressure is Pascal. Dimension of Joule, i.e., work `=FxxL=MLT^(2)xxL=[M^(2)T^(-2)]` `1/(Pa)=1/Pressure=1/(F/A)=(1xxA)/F=[MLT^(-1)]` So, `Jpa^(-1)=[M^(2)T^(2)]=[L^(2)xxL]=[L^(3)]` |
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