The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. Teh oxidation of `C` in diamonds isA. `0`B. `+1`C. `-1`D. `+2`

The valancy of carbons is generally `4`, but its oxidation state may b

1.	The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. Teh oxidation of `C` in diamonds isA. `0`B. `+1`C. `-1`D. `+2`
Answer» Correct Answer - A Carbon in diamond is in elemental state, so the oxidation state of `C` in diamond is zero.

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