The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of carbon is zero?A. `CH_(4)`B. `CH_(3)OH`C. `HCOOH`D. `C_(6)H_(12)O_(6)`

The valancy of carbons is generally `4`, but its oxidation state may b

1.	The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of carbon is zero?A. `CH_(4)`B. `CH_(3)OH`C. `HCOOH`D. `C_(6)H_(12)O_(6)`
Answer» Correct Answer - D a. `overset(-4+1xx4)(CH_(4))` oxidation state of `C=4-4` b. `CH_(3)OH: x+4-2=0 impliesx= -2` c. `HCOOH:x+2-4 =0implies x=2` d. `C_(6)H_(12)O_(6): 6x+12-12=0 implies x=0`.

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