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The value of `[100(x-1)]` is where [x] is the greatest integer less than or equal to x and `x=(sum_(n=1)^44 cos n^@)/(sum_(n=1)^44 sin n^@)` |
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Answer» Correct Answer - 2 `x=(underset(n=1)overset(44)(.sum)cosn^(0))/(underset(n=1)overset(44)(.sum)sinn^(0))=(cos1^(0)+cos2^(0)+"...."cos44^(0))/(sin1^(0)+sin2^(0)+"...."sin44^(0))` `((sin((44)/(2))^(0))/(sin((1)/(2))^(0))cos((1^(0)+44^(0))/(2)))/((sin((44)/(2))^(0))/(sin((1)/(2))^(0))sin((1^(0)+44^(0))/(2)))` `rArr cot((45^(@))/(2))rArr cot(22(1^(@))/(2))` `rArr x=(sqrt2+1)=2.414` |
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