InterviewSolution
Saved Bookmarks
| 1. |
The value of "^(12)C_(2)+^(13)C_(3)+^(14)C_(4)+...+^(999)C_(989) is |
|
Answer» `"^(1000)C_(11)-12` `=.^(1000)C_(989)=.^(1000)C_(11)` (Since, `.^(10)C_(0)=.^(11)C_(0)` and `.^(n)C_(r )+.^(n)C_(r-1)=.^(n+1)C_(r )`) So, `.^(12)C_(2)+.^(13)C_(3)+.^(14)C_(4)+....+.^(999)C_(989)=.^(1000)C_(11)-12` |
|