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The value of .............. |
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Answer» `I=2 int_(0)^(pi) f(x) dx` [f(x) is EVEN] `I=2.2 int_(0)^(pi//2) f(x) dx` `:' f(pi-x) = f(x)` `I= 4 int_(0)^(pi//2) f(x) dx =4 l_(1)` Now, `l_(1)= int_(0)^(pi//2) f(x)dx` `l_(1)=-l_(1)` `:' f(pi/2 -x)=-f(x)` `l_(1)=0` `IMPLIES l=0` |
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