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The value of (5C0 + 5C1) + (5C1 + 5C2) + (5C2 + 5C3) + (5C3 + 5C4) + (5C4 + 5C5) is: (a) 26 – 2 (b) 25 – 1 (c) 28 (d) 27 |
Answer» (a) 26 – 2 (5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5) + (5C1 + 5C2 + 5C3 + 5C4) = 25 + (5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5) – (5C0 + 5C5) = 25 + 25 – (1 + 1) (∵ Adding and subtracting of 5C0 and 5C5) = 2(25) – 2 (∵ 5C0 = 5C5 = 1) = 26 – 2 |
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