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The value of 64a3 + 48a2b + 12a2b+b3 at a= 1 and b = -1 is(a) 25 (b) 125 (c) 27 (d) 54 |
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Answer» (c) 27 64a3 + 48a2b + 12a2b + b3 ⇒ (4a + b)3 [∴ (a + b)2 = a3 + b3 + 3a2b + 3ab2] ∴ Reqd. value = (4-1)3 = 33 = 27. |
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