1.

The value of 6th term from the beggining of (2log2√9x−1+7+1215log2(3x−1+1))7=84 then value of x is

Answer»

The value of 6th term from the beggining of (2log29x1+7+1215log2(3x1+1))7=84 then value of x is



Discussion

No Comment Found