The value of 7∑k=0[(7k)(14k)⋅14∑r=k(rk)(14r)], where (nr) denot – InterviewSolution

1.	The value of 7∑k=0[(7k)(14k)⋅14∑r=k(rk)(14r)], where (nr) denotes nCr is ab. Then the value of a+b is (where a and b are coprime numbers)
Answer» The value of $7 \sum k = 0 [\frac{(\begin{matrix} 7 k \end{matrix})}{(\begin{matrix} 14 k \end{matrix})} \cdot 14 \sum r = k (\begin{matrix} r k \end{matrix}) (\begin{matrix} 14 r \end{matrix})],$ where $(\begin{matrix} n r \end{matrix})$ denotes $^{n} C_{r}$ is $a^{b} .$ Then the value of $a + b$ is (where $a$ and $b$ are coprime numbers)

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