1.

The value of 99^(50)-(99)/(1)*98^(50)+(99.98)/(1.2)97^(50)-……-(99.98)/(1.2)*2^(50)+(99)/(1)*1^(50) is

Answer»

`0`
`-1`
`-2`
`-3`

Solution :`(a)` `99^(50)-99.98^(50)+(99.98)/(1.2)(97)^(50)-....+99`
`=^(99)C_(0)99^(50)-^(99)C_(1)(99-1)^(50)+^(99)C_(2)(99-2)^(50)-....+^(99)C_(98)(99-98)^(50)+^(99)C_(99)(99-99)^(50)`
`=99^(50)('^(99)C_(0)-^(99)C_(1)+^(99)C_(2)-^(99)C_(3)+...)+^(50)C_(1)*99^(49)('^(99)C_(1)-2*^(99)C_(2)+3*^(99)C_(3)-....)+....`
`=0+0+0+....+0=0`


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